Mumbai Indians vs Kings XI Punjab IPL 2017 Match 22 : MI Wins toss and opts to bowl first

Mumbai Indians vs Kings XI Punjab

In the 22nd match of Indian Premier League, Mumbai Indians have won the toss results. Led by Rohit Sharma, team MI has elected to bowl first. Kings XI Punjab will have to bat first in this match. The game is set to start at sharp 8:00 PM, according to IST. The match is being played at Holkar Cricket stadium, which is located in Indore.

At 7:30 PM today, the two captains – Rohit Sharma and Glenn Maxwell gathered in the ground for the toss. Mumbai Indians’ skipper won the toss and while expressing his opinion after the toss results, he said that they would bat first. In Mumbai Indians’ last match, which was played against Gujarat Lions, the team’s captain had taken similar decision after winning the toss.

Mumbai Indians vs Kings XI Punjab

Performance of Mumbai Indians team has been admirable in this tournament as the team has succeeded in winning four matches out of five matches. The MI team holds third rank in IPL 2017 points table and has a net run rate of +0.302. The team is already in safer zone and defeat in this game isn’t going to hamper its position in the same table.

On other hand, Kings XI Punjab has a necessity of winning the game so as to improve its rank in IPL 2017 points. Presently, it is ranking on 5th position in the same table. It has won only two matches out of five games. The team won initial two matches and faced defeats in three consecutive matches. It has a net run rate of -0.302.